... | ... | @@ -94,7 +94,7 @@ Finally, the light intensity that can be observed by the observer behind the lin |
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```math
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I = |E_{6}\cdot \hat{y}|^2 = I_0sin^2\Delta = I_0sin^2(\frac{2\pi(\sigma_1-\sigma_2)}{f_{\sigma}}h)
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```
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Note for a transmission polariscope the corresponding expression is $`I_0sin^2\frac{\Delta}{2}`$. This different needs to be taken care of when solving the contact forces by nonlinear fitting -- the stress-optic relation used in transmission polariscope can not be used directly to fit the patterns recorded by the reflection polariscope. Also note when $\Delta=0$, i.e., for a stress-free specimen or no specimen, $I=0$. This is why metal looks black under a circular polarizer with wave plate side towards the metal.
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Note for a transmission polariscope the corresponding expression is $`I_0sin^2\frac{\Delta}{2}`$. This different needs to be taken care of when solving the contact forces by nonlinear fitting -- the stress-optic relation used in transmission polariscope can not be used directly to fit the patterns recorded by the reflection polariscope. Also note when $`\Delta=0`$, i.e., for a stress-free specimen or no specimen, $`I=0`$. This is why metal looks black under a circular polarizer with wave plate side towards the metal.
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### 2.2. Chirality change of circular polarized light by reflection
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